4c^2+3c-10=(c+2)(4c-5)

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Solution for 4c^2+3c-10=(c+2)(4c-5) equation: 



4c^2+3c-10=(c+2)(4c-5)

We move all terms to the left:

4c^2+3c-10-((c+2)(4c-5))=0

We multiply parentheses ..

4c^2-((+4c^2-5c+8c-10))+3c-10=0



We calculate terms in parentheses: -((+4c^2-5c+8c-10)), so:

(+4c^2-5c+8c-10)

We get rid of parentheses

4c^2-5c+8c-10

We add all the numbers together, and all the variables

4c^2+3c-10

Back to the equation:

-(4c^2+3c-10)



We add all the numbers together, and all the variables

4c^2+3c-(4c^2+3c-10)-10=0

We get rid of parentheses

4c^2-4c^2+3c-3c+10-10=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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